shift the number to left two times and subtract once... I.e.

Int x=num;
x=x<<2;
x-=num;

On 7/30/11, brijesh <brijeshupadhyay...@gmail.com> wrote:
> @ankur I didnt get this... could u or anyone please elaborate!
>
> On Jul 30, 12:43 am, Ankur Khurana <ankur.kkhur...@gmail.com> wrote:
>> when you use itoa , what you get is a string. get the sum of all the
>> digits
>> , using c-'0' and then use repeated subtraction . . .
>>
>> On Sat, Jul 30, 2011 at 1:01 AM, sukhmeet singh
>> <sukhmeet2...@gmail.com>wrote:
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> > repeated subtraction !!
>>
>> > On Sat, Jul 30, 2011 at 12:52 AM, nivedita arora <
>> > vivaciousnived...@gmail.com> wrote:
>>
>> >> Without using /,% and * operators. write a function to divide a number
>> >> by 3. itoa() function is available.
>>
>> >> all i cn thnk of is to use shift operator and addition ,  x/3=e^(logx-
>> >> log3) or repetitive subtraction
>>
>> >> but none of them uses itoa() ..ne idea how its done?
>> >> thnks !
>>
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>> --
>> Ankur Khurana
>> Computer Science
>> Netaji Subhas Institute Of Technology
>> Delhi.
>
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-- 
Thanks&Regards,
Anantha Krishna Sharma.Kalle
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