5)
Sample space=24C2= 276
N(S) = 12 C 2 + 12 C 2 =132

Probability= 132/276= 11/23


*Muthuraj R
IV th Year , ISE
PESIT , Bangalore*



On Wed, Aug 3, 2011 at 10:36 PM, Prakash D <cegprak...@gmail.com> wrote:

> assume there are 6 1's and 6 0's
>
> if two are selected together randomly%
> the possible outcomes are 00, 11, 01, 10
>
> 00- 30 possibilities
> 11 - 30 possibilities
>
> 10 - 36 possibilities
> 01 - 36 possibilities
>
>
> probability of 10  or 01 =  (36+36)/(30+30+36+36)
>
> =18/31
>
>  is it one of the options?
>
>
> On Wed, Aug 3, 2011 at 10:28 PM, JAIDEV YADAV <jaid...@gmail.com> wrote:
>
>> there is no error in first question ... u thik so.. correct me if wrong
>> ...
>>
>>
>> On Wed, Aug 3, 2011 at 10:26 PM, Kamakshii Aggarwal <
>> kamakshi...@gmail.com> wrote:
>>
>>> i think dere is nothing wrong in ques 1.is there any error?
>>>
>>>
>>> On Wed, Aug 3, 2011 at 9:46 PM, cegprakash <cegprak...@gmail.com> wrote:
>>>
>>>> 2 is pretty easy..
>>>>
>>>> 3: both
>>>>
>>>> 5: 6/12 * 6/11  = 3/11
>>>>
>>>> am i right?
>>>>
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>>>
>>>
>>> --
>>> Regards,
>>> Kamakshi
>>> kamakshi...@gmail.com
>>>
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>>
>>
>> --
>> JaiDev Yadav
>> (National Yoga Champion)
>> Computer Engg. Dept.
>> National Institute of Technology
>> Kurukshetra,Haryana
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