prakash its 11/23 only

On Wed, Aug 3, 2011 at 10:45 PM, Prakash D <cegprak...@gmail.com> wrote:

> 18/33?
>
>
> On Wed, Aug 3, 2011 at 10:42 PM, muthu raj <muthura...@gmail.com> wrote:
>
>> 5)
>> Sample space=24C2= 276
>> N(S) = 12 C 2 + 12 C 2 =132
>>
>> Probability= 132/276= 11/23
>>
>>
>> *Muthuraj R
>> IV th Year , ISE
>> PESIT , Bangalore*
>>
>>
>>
>> On Wed, Aug 3, 2011 at 10:36 PM, Prakash D <cegprak...@gmail.com> wrote:
>>
>>> assume there are 6 1's and 6 0's
>>>
>>> if two are selected together randomly%
>>> the possible outcomes are 00, 11, 01, 10
>>>
>>> 00- 30 possibilities
>>> 11 - 30 possibilities
>>>
>>> 10 - 36 possibilities
>>> 01 - 36 possibilities
>>>
>>>
>>> probability of 10  or 01 =  (36+36)/(30+30+36+36)
>>>
>>> =18/31
>>>
>>>  is it one of the options?
>>>
>>>
>>> On Wed, Aug 3, 2011 at 10:28 PM, JAIDEV YADAV <jaid...@gmail.com> wrote:
>>>
>>>> there is no error in first question ... u thik so.. correct me if wrong
>>>> ...
>>>>
>>>>
>>>> On Wed, Aug 3, 2011 at 10:26 PM, Kamakshii Aggarwal <
>>>> kamakshi...@gmail.com> wrote:
>>>>
>>>>> i think dere is nothing wrong in ques 1.is there any error?
>>>>>
>>>>>
>>>>> On Wed, Aug 3, 2011 at 9:46 PM, cegprakash <cegprak...@gmail.com>wrote:
>>>>>
>>>>>> 2 is pretty easy..
>>>>>>
>>>>>> 3: both
>>>>>>
>>>>>> 5: 6/12 * 6/11  = 3/11
>>>>>>
>>>>>> am i right?
>>>>>>
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>>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Regards,
>>>>> Kamakshi
>>>>> kamakshi...@gmail.com
>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> JaiDev Yadav
>>>> (National Yoga Champion)
>>>> Computer Engg. Dept.
>>>> National Institute of Technology
>>>> Kurukshetra,Haryana
>>>>
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-- 
Regards,
Kamakshi
kamakshi...@gmail.com

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