double 87.5 gives you 175
100 will be used by 1st well and 75 will be used by second
now second well will double the 75 and will give you 150
100 will be used by second and remainder 50 will forwarded to third
now third one use 50 and will double it to 100

no remainder left....
i think its clear now  :) :)

On Fri, Aug 5, 2011 at 12:14 AM, Himanshu Srivastava <
himanshusri...@gmail.com> wrote:

> i mean @sagar:how did you get 87.5%??
>
>
> On Fri, Aug 5, 2011 at 12:13 AM, Himanshu Srivastava <
> himanshusri...@gmail.com> wrote:
>
>> @nikhil:how did you get 87.5%??
>>
>> On Thu, Aug 4, 2011 at 11:59 PM, sagar pareek <sagarpar...@gmail.com>wrote:
>>
>>> 87.5 %
>>>
>>> On Thu, Aug 4, 2011 at 10:39 PM, Nikhil Gupta <nikhilgupta2...@gmail.com
>>> > wrote:
>>>
>>>> There are 3 magical wells. Any input quantity of water we provide the
>>>> 1st well is returned double (of this double, half is kept inside the well,
>>>> and the other half is used as input to the 2nd well).
>>>> The 2nd well also returns double the quantity of its input (of which
>>>> half is kept inside the well, and the other half is used as input to the 
>>>> 3rd
>>>> well). Same goes with the 3rd, but its half output is the remainder (other
>>>> half being kept inside the well). Now what input should we provide in the
>>>> 1st well, so that the remainder at the end comes out to be zero?
>>>>
>>>> (Asked in classroom coaching of T.I.M.E.)
>>>> --
>>>> Nikhil Gupta
>>>> Senior Co-ordinator, Publicity
>>>> CSI, NSIT Students' Branch
>>>> NSIT, New Delhi, India
>>>>
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>>>>
>>>
>>>
>>>
>>> --
>>> **Regards
>>> SAGAR PAREEK
>>> COMPUTER SCIENCE AND ENGINEERING
>>> NIT ALLAHABAD
>>>
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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