@Sidharam

I dont think your idea goes along with the sample i/p & o/p

On Aug 5, 9:35 am, siddharam suresh <siddharam....@gmail.com> wrote:
> my idea is "go for inorder traversal find the longest sorted sequence in
> traversal thats the *'largest BST in a binary tree.'* "
> Thank you,
> Siddharam
>
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>
>
> On Fri, Aug 5, 2011 at 10:00 AM, Aman Goyal <aman.goya...@gmail.com> wrote:
> > while dequing  a node from the queue, how will u check whether a bst
> > property is sattisfied or not ?..
>
> > On Fri, Aug 5, 2011 at 9:49 AM, Dipankar Patro <dip10c...@gmail.com>wrote:
>
> >> I have some upto this much currently.
> >> Modify the Breadth First traversal (BFT) a bit. maintain two queues, one
> >> is for original traversal.
>
> >> Start from root,  BFT. when you dequeue a node, check if it satisfies the
> >> condition for BST. if yes add the the node to auxiliary queue, if not, 
> >> leave
> >> it and add it's original children to the original queue in both cases.
> >> Some further modifications can the done to have multiple auxiliary queues
> >> and keep track of their heights.
>
> >> What say?
>
> >> On 5 August 2011 09:40, Aman Goyal <aman.goya...@gmail.com> wrote:
>
> >>> Yes, that can be a liable case definitely....!!!
>
> >>> On Fri, Aug 5, 2011 at 9:35 AM, Dipankar Patro <dip10c...@gmail.com>wrote:
>
> >>>> The question is a bit tricky.
> >>>> Is it possible that the largest BST is somewhere in deeper depth, i.e.
> >>>> it is not necessarily consisting of the root?
>
> >>>> On 5 August 2011 08:46, Aman Goyal <aman.goya...@gmail.com> wrote:
>
> >>>>> How to find the largest BST in a binary tree.
>
> >>>>> 15
> >>>>> / \
> >>>>> 10__________ 20
> >>>>> / \
> >>>>> 5 _____7____
> >>>>> / \
> >>>>> 2_ __5
> >>>>> / \    /
> >>>>> 0 8 3
>
> >>>>> The largest BST (may or may not include all of its descendants) from
> >>>>> the above example should be:
>
> >>>>> ____15____
> >>>>> / \
> >>>>> _10 20
> >>>>> /
> >>>>> 5
>
> >>>>> Please do not post working code, logic/algorithm or link would be
> >>>>> preferred.
> >>>>> I know it will be through recursion  , still the logic part of
> >>>>> recursion is not clear.. would be thankful if anyone could help.
>
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