@Sidharam
Sorry!
I just missed a point.It should be fine.

On Aug 5, 10:00 am, siddharam suresh <siddharam....@gmail.com> wrote:
> @ toarunb...@gmail.com:
> can you tell me flaw in algo(or sample input)!
> Thank you,
> Siddharam
>
>
>
>
>
>
>
> On Fri, Aug 5, 2011 at 10:28 AM, Arun <toarunb...@gmail.com> wrote:
> > @Sidharam
>
> > I dont think your idea goes along with the sample i/p & o/p
>
> > On Aug 5, 9:35 am, siddharam suresh <siddharam....@gmail.com> wrote:
> > > my idea is "go for inorder traversal find the longest sorted sequence in
> > > traversal thats the *'largest BST in a binary tree.'* "
> > > Thank you,
> > > Siddharam
>
> > > On Fri, Aug 5, 2011 at 10:00 AM, Aman Goyal <aman.goya...@gmail.com>
> > wrote:
> > > > while dequing  a node from the queue, how will u check whether a bst
> > > > property is sattisfied or not ?..
>
> > > > On Fri, Aug 5, 2011 at 9:49 AM, Dipankar Patro <dip10c...@gmail.com
> > >wrote:
>
> > > >> I have some upto this much currently.
> > > >> Modify the Breadth First traversal (BFT) a bit. maintain two queues,
> > one
> > > >> is for original traversal.
>
> > > >> Start from root,  BFT. when you dequeue a node, check if it satisfies
> > the
> > > >> condition for BST. if yes add the the node to auxiliary queue, if not,
> > leave
> > > >> it and add it's original children to the original queue in both cases.
> > > >> Some further modifications can the done to have multiple auxiliary
> > queues
> > > >> and keep track of their heights.
>
> > > >> What say?
>
> > > >> On 5 August 2011 09:40, Aman Goyal <aman.goya...@gmail.com> wrote:
>
> > > >>> Yes, that can be a liable case definitely....!!!
>
> > > >>> On Fri, Aug 5, 2011 at 9:35 AM, Dipankar Patro <dip10c...@gmail.com
> > >wrote:
>
> > > >>>> The question is a bit tricky.
> > > >>>> Is it possible that the largest BST is somewhere in deeper depth,
> > i.e.
> > > >>>> it is not necessarily consisting of the root?
>
> > > >>>> On 5 August 2011 08:46, Aman Goyal <aman.goya...@gmail.com> wrote:
>
> > > >>>>> How to find the largest BST in a binary tree.
>
> > > >>>>> 15
> > > >>>>> / \
> > > >>>>> 10__________ 20
> > > >>>>> / \
> > > >>>>> 5 _____7____
> > > >>>>> / \
> > > >>>>> 2_ __5
> > > >>>>> / \    /
> > > >>>>> 0 8 3
>
> > > >>>>> The largest BST (may or may not include all of its descendants)
> > from
> > > >>>>> the above example should be:
>
> > > >>>>> ____15____
> > > >>>>> / \
> > > >>>>> _10 20
> > > >>>>> /
> > > >>>>> 5
>
> > > >>>>> Please do not post working code, logic/algorithm or link would be
> > > >>>>> preferred.
> > > >>>>> I know it will be through recursion  , still the logic part of
> > > >>>>> recursion is not clear.. would be thankful if anyone could help.
>
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