According to me if we get even number in first case then the series will end there only as we just need an even sum. Similarly in case of e(3) the only possible sequence for which the sum is even in exactly 3 turns is odd then even and then odd.
On Sat, Aug 6, 2011 at 11:40 PM, Mukul Gupta <mukul.gupta...@gmail.com>wrote: > E(x)= 1 x (1/2) + 2 x (1/2 x 1/2 (Odd-Odd) + 1/2 x 1/2 (Even-Even) + 3 (1/4 > x 1/2 (Odd-Odd-Even)+ 1/4 x 1/2 (Odd-Even-Odd)+ 1/4 x 1/2 (Even-Odd-Odd)+ > 1/4 x 1/2(Even-Even-Even) )+.... > E(x)= 1/2 + 1 + 3/2 ..... > According to me, since the series does not converge, Expectation value does > not exist. > > @Kunal: For E(2)...The running sum can be even if > (i) On the first die, we get an odd and then again an odd. > (ii) On the first die, we get an even and then again an even. > > How have you considered only a single case? > > Please correct if I'm wrong. > > Regards, > > Mukul Gupta > 3rd Year, COE > NSIT > > > On Sat, Aug 6, 2011 at 11:22 PM, Kunal Yadav <kunalyada...@gmail.com>wrote: > >> Hey sry for my above post. I got a little confused. x is the no of times >> dice is rolled so >> e(x)=e(1)+e(2)+e(3)+.... >> =1/2 + 2*1/(2*2) + 3*1/(2*2*2) + ...... >> Please correct me if m wrong.. >> >> On Sat, Aug 6, 2011 at 10:54 PM, Kunal Yadav <kunalyada...@gmail.com>wrote: >> >>> Expected value of a random variable x is defined as E(x)= summation of >>> xp(x) over all value of x where p(x) is the probability. >>> so in this case >>> E(x)= E(2)+E(4)+ E(6)+ ..... >>> = 2*1/6 + 4* 3/(6*6)+ 6*10/(6*6*6) + ..... >>> >>> >>> On Sat, Aug 6, 2011 at 9:19 PM, sukran dhawan <sukrandha...@gmail.com>wrote: >>> >>>> >>>> >>>> On Sat, Aug 6, 2011 at 8:24 PM, muthu raj <muthura...@gmail.com> wrote: >>>> >>>>> Microsoft written: >>>>> >>>>> What is the probability of getting atleast one 6 in 3 attempts of a >>>>> dice? >>>>> >>>>> probability of not getting 6 = 5/6 * 5/6 * 5/6 = 91/216 >>>>> >>>> so ans 1- 91/216 >>>> let me know how was the paper and the pattern >>>> >>>>> *Muthuraj R >>>>> IV th Year , ISE >>>>> PESIT , Bangalore* >>>>> >>>>> >>>>> >>>>> >>>>> On Sat, Aug 6, 2011 at 7:34 AM, shady <sinv...@gmail.com> wrote: >>>>> >>>>>> Hi, >>>>>> >>>>>> A fair dice is rolled. Each time the value is noted and running sum is >>>>>> maintained. What is the expected number of runs needed so that the sum is >>>>>> even ? >>>>>> Can anyone tell how to solve this problem ? as well as other related >>>>>> problems of such sort.... >>>>>> >>>>>> -- >>>>>> You received this message because you are subscribed to the Google >>>>>> Groups "Algorithm Geeks" group. >>>>>> To post to this group, send email to algogeeks@googlegroups.com. >>>>>> To unsubscribe from this group, send email to >>>>>> algogeeks+unsubscr...@googlegroups.com. >>>>>> For more options, visit this group at >>>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>>> >>>>> >>>>> -- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "Algorithm Geeks" group. >>>>> To post to this group, send email to algogeeks@googlegroups.com. >>>>> To unsubscribe from this group, send email to >>>>> algogeeks+unsubscr...@googlegroups.com. >>>>> For more options, visit this group at >>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>> >>>> >>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "Algorithm Geeks" group. >>>> To post to this group, send email to algogeeks@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> algogeeks+unsubscr...@googlegroups.com. >>>> For more options, visit this group at >>>> http://groups.google.com/group/algogeeks?hl=en. >>>> >>> >>> >>> >>> -- >>> Regards >>> Kunal Yadav >>> (http://algoritmus.in/) >>> >>> >> >> >> -- >> Regards >> Kunal Yadav >> (http://algoritmus.in/) >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
