@Kunal: Perhaps, you are right :) On Sat, Aug 6, 2011 at 11:45 PM, Kunal Yadav <kunalyada...@gmail.com> wrote:
> According to me if we get even number in first case then the series will > end there only as we just need an even sum. Similarly in case of e(3) the > only possible sequence for which the sum is even in exactly 3 turns is odd > then even and then odd. > > On Sat, Aug 6, 2011 at 11:40 PM, Mukul Gupta <mukul.gupta...@gmail.com>wrote: > >> E(x)= 1 x (1/2) + 2 x (1/2 x 1/2 (Odd-Odd) + 1/2 x 1/2 (Even-Even) + 3 >> (1/4 x 1/2 (Odd-Odd-Even)+ 1/4 x 1/2 (Odd-Even-Odd)+ 1/4 x 1/2 >> (Even-Odd-Odd)+ 1/4 x 1/2(Even-Even-Even) )+.... >> E(x)= 1/2 + 1 + 3/2 ..... >> According to me, since the series does not converge, Expectation value >> does not exist. >> >> @Kunal: For E(2)...The running sum can be even if >> (i) On the first die, we get an odd and then again an odd. >> (ii) On the first die, we get an even and then again an even. >> >> How have you considered only a single case? >> >> Please correct if I'm wrong. >> >> Regards, >> >> Mukul Gupta >> 3rd Year, COE >> NSIT >> >> >> On Sat, Aug 6, 2011 at 11:22 PM, Kunal Yadav <kunalyada...@gmail.com>wrote: >> >>> Hey sry for my above post. I got a little confused. x is the no of times >>> dice is rolled so >>> e(x)=e(1)+e(2)+e(3)+.... >>> =1/2 + 2*1/(2*2) + 3*1/(2*2*2) + ...... >>> Please correct me if m wrong.. >>> >>> On Sat, Aug 6, 2011 at 10:54 PM, Kunal Yadav <kunalyada...@gmail.com>wrote: >>> >>>> Expected value of a random variable x is defined as E(x)= summation of >>>> xp(x) over all value of x where p(x) is the probability. >>>> so in this case >>>> E(x)= E(2)+E(4)+ E(6)+ ..... >>>> = 2*1/6 + 4* 3/(6*6)+ 6*10/(6*6*6) + ..... >>>> >>>> >>>> On Sat, Aug 6, 2011 at 9:19 PM, sukran dhawan >>>> <sukrandha...@gmail.com>wrote: >>>> >>>>> >>>>> >>>>> On Sat, Aug 6, 2011 at 8:24 PM, muthu raj <muthura...@gmail.com>wrote: >>>>> >>>>>> Microsoft written: >>>>>> >>>>>> What is the probability of getting atleast one 6 in 3 attempts of a >>>>>> dice? >>>>>> >>>>>> probability of not getting 6 = 5/6 * 5/6 * 5/6 = 91/216 >>>>>> >>>>> so ans 1- 91/216 >>>>> let me know how was the paper and the pattern >>>>> >>>>>> *Muthuraj R >>>>>> IV th Year , ISE >>>>>> PESIT , Bangalore* >>>>>> >>>>>> >>>>>> >>>>>> >>>>>> On Sat, Aug 6, 2011 at 7:34 AM, shady <sinv...@gmail.com> wrote: >>>>>> >>>>>>> Hi, >>>>>>> >>>>>>> A fair dice is rolled. Each time the value is noted and running sum >>>>>>> is maintained. What is the expected number of runs needed so that the >>>>>>> sum is >>>>>>> even ? >>>>>>> Can anyone tell how to solve this problem ? as well as other related >>>>>>> problems of such sort.... >>>>>>> >>>>>>> -- >>>>>>> You received this message because you are subscribed to the Google >>>>>>> Groups "Algorithm Geeks" group. >>>>>>> To post to this group, send email to algogeeks@googlegroups.com. >>>>>>> To unsubscribe from this group, send email to >>>>>>> algogeeks+unsubscr...@googlegroups.com. >>>>>>> For more options, visit this group at >>>>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>>>> >>>>>> >>>>>> -- >>>>>> You received this message because you are subscribed to the Google >>>>>> Groups "Algorithm Geeks" group. >>>>>> To post to this group, send email to algogeeks@googlegroups.com. >>>>>> To unsubscribe from this group, send email to >>>>>> algogeeks+unsubscr...@googlegroups.com. >>>>>> For more options, visit this group at >>>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>>> >>>>> >>>>> -- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "Algorithm Geeks" group. >>>>> To post to this group, send email to algogeeks@googlegroups.com. >>>>> To unsubscribe from this group, send email to >>>>> algogeeks+unsubscr...@googlegroups.com. >>>>> For more options, visit this group at >>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>> >>>> >>>> >>>> >>>> -- >>>> Regards >>>> Kunal Yadav >>>> (http://algoritmus.in/) >>>> >>>> >>> >>> >>> -- >>> Regards >>> Kunal Yadav >>> (http://algoritmus.in/) >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Regards > Kunal Yadav > (http://algoritmus.in/) > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. 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