The solution is 5/6 for sure

the possible outcomes after a blue is chosen are

blue   1 1 0
black  0 1 2

and

blue   2 0 0
black  0 1 2

prob of choosing a blue from 1st possibility = 1/3+1/6

prob of choosing a blue from 2nd possibility= 1/3

so totally there are 5/6 possibilities



On Sun, Aug 7, 2011 at 3:05 PM, Kunal Yadav <kunalyada...@gmail.com> wrote:

> Agree with puneet completely. After first blue pen, only possible outcomes
> are blue or black and hence 1/2.
>
>
> On Sat, Aug 6, 2011 at 12:28 AM, Puneet Goyal <puneetgoya...@gmail.com>wrote:
>
>>
>> @shiv : you are considering the case when you need to know the probability
>> of both pens being blue, but in the question you already know that 1st one
>> is blue so you dont need to care about it, and also the 3rd packet getting
>> eliminated coz of it increases the probability to 1/2
>>
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> Kunal Yadav
> (http://algoritmus.in/)
>
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