On Mon, Aug 8, 2011 at 12:47 AM, aseem garg <ase.as...@gmail.com> wrote:

> Think it like this. I have tossed a coin 5 times and it showed heads all
> the times. What is the probabilty of it shoing a HEADS now?
> Aseem
>

Well you are thinking about it the wrong way. Question asks that what is the
probability that heads will show up the first five times, plus a sixth time.
Not just the sixth time. The first five times head showing up is part of the
question.



>
>
>
> On Mon, Aug 8, 2011 at 1:12 AM, Shuaib Khan <aries.shu...@gmail.com>wrote:
>
>>
>>
>> On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam 
>> <puneet.nsi...@gmail.com>wrote:
>>
>>> Sixth toss is independent of previous tosses and dependent only on
>>> coin selection...!
>>>
>>> 1/5 + 4/5(1/2)= 3/5
>>>
>>> is the correct answer....
>>>
>>> we want to calc. probability of getting heads the sixth time only....
>>> even if it would have been 100 th time...3/5 would be the answer
>>> only..
>>>
>>>
>> It is not independent. Re read the question. The first five times, it HAS
>> to be heads.
>>
>>>
>>> On 8/8/11, Prakash D <cegprak...@gmail.com> wrote:
>>> > 1.) coin is fair
>>> > 2.) coin is unfair
>>> >
>>> > P(head) for unfair coin= 1/5 * 1= 1/5
>>> > P(head) for fair coin= 4/5* 1/2 = 2/5
>>> >
>>> >
>>> > the probability at any instant that the tossed coin is a head is 3/5
>>> >
>>> > 17/80 is the probability to get head at all the six times.
>>> >
>>> > the soln. for this problem will be 3/5
>>> >
>>> > On Mon, Aug 8, 2011 at 12:45 AM, aseem garg <ase.as...@gmail.com>
>>> wrote:
>>> >
>>> >> If the coin is unbiased then probability of heads: 1/2 irrespective of
>>> >> whether it is first time or nth time. So answer should be 3/5.
>>> >> Aseem
>>> >>
>>> >>
>>> >>
>>> >> On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra
>>> >> <saurabh131...@gmail.com>wrote:
>>> >>
>>> >>> Even u dont get why u people are gettin 17/80...the probability that
>>> >>> it will be a head 6th time will be same as the frst time...so it shud
>>> >>> be 3/5...
>>> >>>
>>> >>> On Aug 7, 11:05 pm, Kunal Yadav <kunalyada...@gmail.com> wrote:
>>> >>> > @algo: We can get head in two cases:-
>>> >>> >
>>> >>> > 1.) coin is biases
>>> >>> > 2.) coin is not biased
>>> >>> >
>>> >>> > P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5
>>> >>> > P(head) for unbiased= 4/5*(1/2)^6
>>> >>> > hence combined probability is what nitish has already mentioned.
>>> Hope
>>> >>> you
>>> >>> > get the point.
>>> >>> >
>>> >>> >
>>> >>> >
>>> >>> >
>>> >>> >
>>> >>> >
>>> >>> >
>>> >>> >
>>> >>> >
>>> >>> > On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover <algolear...@gmail.com
>>> >
>>> >>> wrote:
>>> >>> > > Can anyone explain the approach how to solve this .
>>> >>> > > I think all tosses are independent so it should be 3/5. why is
>>> this
>>> >>> in-
>>> >>> > > correct
>>> >>> >
>>> >>> > > On Aug 7, 10:55 pm, saurabh chhabra <saurabh131...@gmail.com>
>>> wrote:
>>> >>> > > > sry...its wrong
>>> >>> >
>>> >>> > > > On Aug 7, 10:34 pm, Algo Lover <algolear...@gmail.com> wrote:
>>> >>> >
>>> >>> > > > > A bag contains 5 coins. Four of them are fair and one has
>>> heads
>>> >>> > > > > on
>>> >>> > > > > both sides. You randomly pulled one coin from the bag and
>>> tossed
>>> >>> it 5
>>> >>> > > > > times, heads turned up all five times. What is the
>>> probability
>>> >>> that
>>> >>> > > > > you toss next time, heads turns up. (All this time you don't
>>> know
>>> >>> you
>>> >>> > > > > were tossing a fair coin or not).
>>> >>> >
>>> >>> > > --
>>> >>> > > You received this message because you are subscribed to the
>>> Google
>>> >>> Groups
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>>> >>> >
>>> >>> > --
>>> >>> > Regards
>>> >>> > Kunal Yadav
>>> >>> > (http://algoritmus.in/)
>>> >>>
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>>
>>
>> --
>> Shuaib
>> http://www.bytehood.com
>> http://twitter.com/ShuaibKhan
>>
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-- 
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