Agree with mohit goel..
On Wed, Aug 10, 2011 at 11:22 AM, Mohit Goel <mohitgoel291...@gmail.com>wrote:
> 10
> 4 5
> 2 7 6 11
> 1 3 9 8 12 13 14 15
>
>
> i think we should first find the parent of the particular node ..then
> apply the concept as told by Brijesh on it ....
>
> p =parent(q);
> r = parent(p);
> count =1;
> while(p ==isright(r))
> {
> p=r;
> r=parent(r);
> count++;
> if(r==root)
> break;
>
> }
>
> if(d =right(r))
> {
> while(count!=0)
> {
> if(d->left)
> d=d->left;
> else d=d->right;
> count--;
> }
> }
> else return NULL;
> o/p=d->value;
>
>
>
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With regards
............
Puneet Chawla
Computer Engineering Student
NIT Kurukshetra
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