@coder dumca: If u apply DFS u will get a brother and not cousin. And yes
it works only for some cases.
*Muthuraj R
IV th Year , ISE
PESIT , Bangalore*
On Wed, Aug 10, 2011 at 2:24 PM, coder dumca <coder.du...@gmail.com> wrote:
> apply BFS
> the node after the particular node(whode cousin to be find) will be the
> required node
>
> On Wed, Aug 10, 2011 at 2:15 PM, Puneet Chawla
> <puneetchawla...@gmail.com>wrote:
>
>>
>> Agree with mohit goel..
>>
>> On Wed, Aug 10, 2011 at 11:22 AM, Mohit Goel
>> <mohitgoel291...@gmail.com>wrote:
>>
>>> 10
>>> 4 5
>>> 2 7 6 11
>>> 1 3 9 8 12 13 14 15
>>>
>>>
>>> i think we should first find the parent of the particular node ..then
>>> apply the concept as told by Brijesh on it ....
>>>
>>> p =parent(q);
>>> r = parent(p);
>>> count =1;
>>> while(p ==isright(r))
>>> {
>>> p=r;
>>> r=parent(r);
>>> count++;
>>> if(r==root)
>>> break;
>>>
>>> }
>>>
>>> if(d =right(r))
>>> {
>>> while(count!=0)
>>> {
>>> if(d->left)
>>> d=d->left;
>>> else d=d->right;
>>> count--;
>>> }
>>> }
>>> else return NULL;
>>> o/p=d->value;
>>>
>>>
>>>
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>>
>>
>>
>> --
>> With regards
>> ............
>> Puneet Chawla
>> Computer Engineering Student
>> NIT Kurukshetra
>>
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