it can be done in O(3n). in worst case one row will have max and anothr row
will have min so the third row will be your o/p to print

On Mon, Aug 15, 2011 at 12:00 AM, Karthikeyan palani <
karthikeyan...@gmail.com> wrote:

> sorry O(n^2) s the time complexity
>
>
> On 14 August 2011 23:56, shady <sinv...@gmail.com> wrote:
>
>> how can it be O(n) when there are itself n*n elements..
>>
>> PS : no sharing of code, else the inevitable
>>
>> On Sun, Aug 14, 2011 at 11:51 PM, Karthikeyan palani <
>> karthikeyan...@gmail.com> wrote:
>>
>>> Given a n x n matrix. .number are randomly placed. .print any one row
>>> which doesn’t have min
>>> and max elements. Time Complexity : 0(n)
>>>
>>>
>>>
>>> if anyone know the code.. pls share!!!
>>>
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>>> karthikeyankkn
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