in frst printf we acess *s and s is incremented later...so it prints A bt at
the same time s points to B now...
In 2nd printf s is incremented frst and thn dereferencd...after incrementing
it points to C and whn we dereference it we get C
in the third printf *s=C whn we increment this we get D
so the ans wud be ACD...
I hope its clear
On Mon, Aug 22, 2011 at 4:03 PM, MANNU <manishkr2...@gmail.com> wrote:
> main()
> {
> char ch[]="ABCD";
> char *s;
> s=ch;
> printf("%c",*s++);
> printf("%c",*++s);
> printf("%c",++*s);
> }
>
> Can anyone plz tell me the concept behind output??
>
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--
Aditi Garg
Undergraduate Student
Electronics & Communication Divison
NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
Sector 3, Dwarka
New Delhi
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