for the 1st printf i hv this explanation:
precedence of ++ is greater then *   ... but associativity of both of
them is right to left...
thats why dereferenced takes place 1st and then the pointer is
incremented...

rest is fine...

correct me if i m wrong...

On Aug 22, 3:47 pm, aditi garg <aditi.garg.6...@gmail.com> wrote:
> in frst printf we acess *s and s is incremented later...so it prints A bt at
> the same time s points to B now...
> In 2nd printf s is incremented frst and thn dereferencd...after incrementing
> it points to C and whn we dereference it we get C
> in the third printf *s=C whn we increment this we get D
> so the ans wud be ACD...
> I hope its  clear
>
>
>
>
>
>
>
>
>
> On Mon, Aug 22, 2011 at 4:03 PM, MANNU <manishkr2...@gmail.com> wrote:
> > main()
> > {
> > char ch[]="ABCD";
> > char *s;
> > s=ch;
> > printf("%c",*s++);
> > printf("%c",*++s);
> > printf("%c",++*s);
> > }
>
> > Can anyone plz tell me the concept behind output??
>
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> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi

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