it takes \n as character on input buffer for each enter keystroke
so use fflush(stdin); before 2nd scanf.
On Wed, Aug 24, 2011 at 6:30 PM, Sanjay Rajpal <srn...@gmail.com> wrote:
> after first scanf, place a call to fflush(stdin).
>
> you will get the result.
>
> Sanju
> :)
>
>
>
> On Wed, Aug 24, 2011 at 5:58 AM, Mehnaaz <mehnaazmohiud...@gmail.com>wrote:
>
>> #include <stdio.h>
>> #define max 30
>> int no_p;
>> int main() {
>>
>> char p[no_p][max];
>> char x;
>> int i=0;
>> printf("enter the no of productions..\n");
>> scanf("%d", &no_p);
>> printf("you have entered :%d\n", no_p);
>> printf("Variable who's FOLLOW you want\n");
>> scanf("%c", &x);
>> printf("you have entered :%c",X);
>> printf("\n");
>> for( i =0 ; i< no_p ; i++){
>> printf("enter the production # %d",i+1);
>> scanf("%s",p[i]);
>> }
>> //follow(p,x);
>> return 0;
>> }
>>
>>
>> the output i am getting goes like this
>> ......................................
>> enter the no of productions..
>> 3
>> you have entered :3
>> Variable who's FOLLOW you want
>> you have entered :
>>
>> enter the production # 1
>> ...........................................
>> at the line 4 of the output its supposed to wait for my scanf() entry
>> value right??..but it executes the printf after that giving "you have
>> entered"
>>
>> i'm using gcc to compile this
>>
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-Warm Regards
LAKSHAY
NIT-K
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