yeah you can do that by opening the file and printing it but as far as I
know, interviewer adds the constraint of not using the file method.

On Sun, Aug 28, 2011 at 12:35 PM, rahul sharma <rahul23111...@gmail.com>wrote:

> this logic is ok...but we have pre defined everything in char f...if i
> add one or two more statements then it will require corresponding
> change in char *f...can i open the same file with f open n prin t it
> out?????
>
> On Aug 28, 11:31 am, Piyush Grover <piyush4u.iit...@gmail.com> wrote:
> > char*f="char*f=%c%s%c;main(){printf(f,34,f,34,10);}%c";
> >
> > f is a global pointer to the char array which contains the string
> > "char*f=%c%s%c;main(){printf(f,34,f,34,10);}%c"
> >
> > Now in main function you are printing this string with arguments
> 34,f,34,10.
> > ASCII value of " is 34.
> > ->So in f, the first %c is replaced by ".
> > ->The next %s is replaced by string f.
> > ->the second %c is replaced by " and
> > ->last %c is replaced by backspace. The last %c is actually I feel not
> > required. So the code can be:
> >
> >
> char*f="char*f=%c%s%c;main(){printf(f,34,f,34);}";main(){printf(f,34,f,34);
> }
> >
> > I hope it helps. Try to do it manually on paper. You would be able to
> > understand it.
> >
> > -Piyush
> >
> > On Sun, Aug 28, 2011 at 11:46 AM, rahul sharma <rahul23111...@gmail.com
> >wrote:
> >
> >
> >
> >
> >
> >
> >
> > > plz expalin char*f="            "
> >
> > > On Aug 28, 11:12 am, Piyush Grover <piyush4u.iit...@gmail.com> wrote:
> > > > it's a quine problem.
> >
> > > > char*f="char*f=%c%s%c;
> > > > main(){
> > > > printf(f,34,f,34,10);}%c";
> >
> > > > main()
> > > > {
> > > > printf(f,34,f,34,10);
> >
> > > > }
> >
> > > > I have used whitespaces to make it understand.
> >
> > > > On Sun, Aug 28, 2011 at 11:39 AM, rahul sharma <
> rahul23111...@gmail.com
> > > >wrote:
> >
> > > > > program whose output is the program itself???????????????
> >
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