this s on geeks for geeks and the answer is 20

On 1 September 2011 00:11, htross <htb...@gmail.com> wrote:

> u r not considering what if the first fork returns non zero and the
> second for returns a zero value then????
>
> On Aug 31, 9:50 pm, rahul vatsa <vatsa.ra...@gmail.com> wrote:
> > int main()
> > {
> >    fork();
> >    fork() && fork() || fork();
> >    fork();
> >    printf("forked\n");
> >    return 0;
> >
> > }
> >
> > ln 1 : will create 2 prs
> > ln 2 : will create 10 process for each existing pr
> > ln 3 : will do fork for all 10 process, nd so now u ve 20 prs
> >
> > the main issue is @ln-2 in main( )
> >
> > Ln 2 :
> >
> > here for 1st fork, if its parent, its ret value in nonzero, so it will
> > proceed for next fork, as that is for &&.  if ret value of this 2nd fork
> is
> > nonzero, it willn't try the 3rd fork (as its nt required, bcoz that comes
> > after ||, nd the st is already a true st) --  > So for parent of 1st fork
> in
> > the st, total no of prs created is 3.
> >
> > if 1st fork returns 0, ie if it is child, it willn't attempt the next
> > fork(bcoz thatz for operator && , and the st is already 0), bt it will do
> > attempt the 3rd fork(bcoz that is for operator ||)  so total no processes
> > created here is - 2
> >
> > Ln 3- this fork is called for all created processes.  2(Ln 1) * 5(ln 2) *
> 2
> > (ln 3) == 20 prs
> >
> > On Wed, Aug 31, 2011 at 12:29 PM, SANDEEP CHUGH <sandeep.aa...@gmail.com
> >wrote:
> >
> >
> >
> >
> >
> >
> >
> > > it will be 16 ..
> >
> > > On Wed, Aug 31, 2011 at 9:54 PM, abhishek <abhishek.ma...@gmail.com
> >wrote:
> >
> > >> i think it will be 16 (not sure )
> >
> > >> can anyone explain how it will be 20,
> > >> On Aug 31, 9:02 pm, SANDEEP CHUGH <sandeep.aa...@gmail.com> wrote:
> > >> > i thinks it is 16 not 20
> >
> > >> > please check that
> >
> > >> > On Wed, Aug 31, 2011 at 9:18 PM, annarao kataru <
> > >> kataruanna...@gmail.com>wrote:
> >
> > >> > > @swathi ::  why  it is  20  times ??   ur answer  is  correct  but
> > >> > > plz  explain the  process??????
> >
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-- 
regards Pratima :)

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