when u pass array as an argument to a function only the starting address is
passed .so sizeof(a) is address of pointer !
On Sat, Sep 3, 2011 at 6:22 PM, priya ramesh <love.for.programm...@gmail.com
> wrote:
> In any C program,
> int main(){
> char a[100];
> foo(a);
> printf("%d", sizeof(a));
> }
> foo(char *s){
> printf("%d", sizeof(a));
> }
>
> In main sizeof a is 100, in foo it is 4. why??
>
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