+1 siddarth

On Sat, Sep 3, 2011 at 2:54 PM, Dheeraj Sharma
<dheerajsharma1...@gmail.com>wrote:

> yeah..we it works for +ve  number..within some specified range..it was
> alternate to O(nlogn) solution..if range is known
>
>
> On Sun, Sep 4, 2011 at 12:07 AM, mohit verma <mohit89m...@gmail.com>wrote:
>
>> @dheeraj - for count sort we need to know the range the numbers are in.
>> Otherwise how will u initialize array keeping count?
>>
>>
>> On Sun, Sep 4, 2011 at 12:03 AM, Dheeraj Sharma <
>> dheerajsharma1...@gmail.com> wrote:
>>
>>> count sort in reverse order would help i guess :)
>>>
>>>
>>> On Sat, Sep 3, 2011 at 11:49 PM, mohit verma <mohit89m...@gmail.com>wrote:
>>>
>>>> Ohh my bad. the complexity should be
>>>> O(nlogn) + O(mlogm) +O(m) = O(tlogt) where t=max(m,n)
>>>>
>>>>
>>>> On Sat, Sep 3, 2011 at 11:46 PM, mohit verma <mohit89m...@gmail.com>wrote:
>>>>
>>>>> create a binary search tree by scanning the whole array and if the
>>>>> value already exists increase count field in that node O(nlogn). Now
>>>>> traverse the tree in any order by creating another tree with kery - count.
>>>>> O(nlogn). Doing reverse inorder traversal print value field of each node
>>>>> count number of times O(n).
>>>>>
>>>>> overall complexity - O(nlogn)+O(nlogn)+O(n) = O(nlogn).
>>>>>
>>>>>
>>>>> On Sat, Sep 3, 2011 at 11:16 PM, Siddhartha Banerjee <
>>>>> thefourrup...@gmail.com> wrote:
>>>>>
>>>>>> perhaps we can make it O(mlogm), m= no of distinct elements... just
>>>>>> create a hash table and store the count of the number of time elements
>>>>>> occur... O(n), now sort the m elements and proceed as above...
>>>>>> it is obviously not possible to do it faster than O(mlogm), where m =
>>>>>> no of distinct elements...
>>>>>> so order = O(n+mlogm)=O(mlogm)(???, assuming m!<<n)
>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> ........................
>>>>> *MOHIT VERMA*
>>>>>
>>>>>
>>>>
>>>>
>>>> --
>>>> ........................
>>>> *MOHIT VERMA*
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>>>
>>>
>>>
>>> --
>>> *Dheeraj Sharma*
>>> Comp Engg.
>>> NIT Kurukshetra
>>> +91 8950264227
>>>
>>>
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>>
>>
>>
>> --
>> ........................
>> *MOHIT VERMA*
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>
>
>
> --
> *Dheeraj Sharma*
> Comp Engg.
> NIT Kurukshetra
> +91 8950264227
>
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