hey guys
why hashing?
can't we simply sort the array of characters in-place - space complexity
O(1) .
and then simply rearrange the array in-place with character+frequency.
On Sun, Sep 4, 2011 at 3:13 PM, bharatkumar bagana <
bagana.bharatku...@gmail.com> wrote:
> +1 rahul and +1 ankuj
>
>
> On Sat, Sep 3, 2011 at 11:37 AM, icy` <vipe...@gmail.com> wrote:
>
>> Just use a hash to count frequency of something; e.g. in ruby:
>> ar= %w(a a b c a b b c d e a d e f)
>> freq=Hash.new(0)
>> ar.each {|c| freq[c]+=1}
>> p freq
>>
>> #output
>> #{"a"=>4, "b"=>3, "c"=>2, "d"=>2, "e"=>2, "f"=>1}
>>
>> you could only do it in place in O(1) only if your input array is
>> already 2*(number of all possible characters) size, but you didnt
>> mention size of input array. For example, what if input was just
>> [a,b,c,d,e] ? The size is 5. You cant just convert the input
>> into [a,1,b,1,c,1,d,1,e,1] without increasing the size to 10. So
>> hash is the better method.
>>
>> On Sep 3, 11:04 am, Ankuj Gupta <ankuj2...@gmail.com> wrote:
>> > if for all inputs you array remains of same size we can take it as
>> > constant space
>> >
>> > On Sep 3, 7:49 pm, rajul jain <rajuljain...@gmail.com> wrote:
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > > @ankuj just want to clarify that in hashing method we require array
>> of
>> > > fixed size let say arr[26] , so is it considered as constant space or
>> not?
>> >
>> > > On Sat, Sep 3, 2011 at 8:02 PM, siddharam suresh <
>> siddharam....@gmail.com>wrote:
>> >
>> > > > sol already posted please search old thread
>> > > > Thank you,
>> > > > Sid.
>> >
>> > > > On Sat, Sep 3, 2011 at 8:01 PM, Ankuj Gupta <ankuj2...@gmail.com>
>> wrote:
>> >
>> > > >> If we take our input to be characters a-z ans A-Z then we require
>> > > >> fixed space which can be treated as O(1).
>> > > >> On Sep 3, 7:10 pm, teja bala <pawanjalsa.t...@gmail.com> wrote:
>> > > >> > this 'll work if u i/p the string in dis manner
>> > > >> > aaabbcc(consecutive same)
>> > > >> > a3b2c2
>> >
>> > > >> > #include<stdio.h>
>> > > >> > #include<conio.h>
>> > > >> > main()
>> > > >> > {
>> > > >> > int x=1,i=0;
>> > > >> > char a[100];
>> > > >> > gets(a);
>> > > >> > while(a[i]!='\0')
>> > > >> > {
>> > > >> > while(a[i]==a[i+1])
>> > > >> > {
>> > > >> > x++;
>> > > >> > i++;
>> > > >> > }
>> > > >> > printf("%c%d",a[i],x);
>> > > >> > x=1;
>> > > >> > i++;
>> > > >> > }
>> > > >> > getchar();
>> >
>> > > >> > }
>> >
>> > > >> --
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