@Rahul: No, no, no. If you double the people and don't change the number of days, you double the number of paintings. Similarly, if you double the number of days and don't change the number of people, you double the number of paintings. The number of paintings is _jointly proportional_ to the number of people and the number of days. Thus, paintings = constant * people * days.
We can use the given data to solve for the constant: 5/2 = c * 5/2 * 5/2, so c = 2/5. Finally, 25 = 2/5 * people * 25, so people = 5/2. Dave On Sep 7, 7:30 am, rahul vatsa <vatsa.ra...@gmail.com> wrote: > i think it should be 1. > 5/2 paintings r made by 5/2 ppl in 5/2 days using 5/2 canvas > =>> 1 painting is made by 1 person in 1 day using 1 canvas > > i.e. 1 guy cn make a painting in 1 day using a canvas. > > Now, the other case, to make 25 paintings using 25 canvases in 25 days. > > As there r 25 days & total paintings required is 25, so u need just 1 guy to > do that. u have here 25 canvases, bt he cn make using just 1. > > > > On Wed, Sep 7, 2011 at 8:15 AM, sush57 <sushaant...@gmail.com> wrote: > > If 5/2 artists make 5/2 paintings using 5/2 canvases in 5/2 days then > > how many artists r > > required to make 25 paintings using 25 canvases in 25 days? > > > some sayin 25,some sayin 1...........can anyone pls explain the answer > > for this puzzle... > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to algogeeks@googlegroups.com. > > To unsubscribe from this group, send email to > > algogeeks+unsubscr...@googlegroups.com. > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
