1.use character count to record frequencey of occurences // initialise array
to 0
2. for(i=0;str[i];i++)
{
if(count[str[i]] == 0) // first repeated character break;
}
On Sun, Sep 11, 2011 at 5:43 PM, Ishan Aggarwal <
ishan.aggarwal.1...@gmail.com> wrote:
> {Please solve the following questions :-
>
> 1.) Find first non repeated character.
>
> eg. total --> o
> teeter --> r
>
> 2.) Remove specified letters from a string.
>
> input --> "Battle of the vowels: Hawaii vs. Gronzy" , "aeiou"
>
> output --> "Bttle f th vwls: Hw vs. Grnzy"
>
> What is the problem in this solution ... Its giving compilation error.
>
>
> #include<stdio.h>#include<string.h>
> void main(){int temp1[256];int i=0;char str[40] = "Battle of the vowels:
> Hawaii vs. Gronzy";char temp[6] = "aeiou";
> for(i=0;i<256;i++)
> temp1[i] = 0;
>
> i=0;while(temp[i]){
> temp1[temp[i]] = 1;
> i++;}
> i=0;while(str[i]){if(temp1[str[i]] == 1){
> str[i] = str[i+1];
> i--;}
> i++;}printf
> <http://www.opengroup.org/onlinepubs/009695399/functions/printf.html>("%s",
> str);}
>
>
>
>
>
>
> --
> Kind Regards
> Ishan Aggarwal
> [image: Aricent Group]
> Presidency Tower-A, M.G.Road,Sector-14
> Gurgaon,Haryana.122015 INDIA
> Phone : +91-9654602663
> ishan2.aggar...@aricent.com <puneet.ar...@aricent.com>
>
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