#include<bitset>
#include<iostream>
#include<queue>
using namespace std;
int main()
{
char answer;
bitset<26> charset;
bitset<26> repeat;
char a[]={'s','a','s','a','b','v','s','a'};
#ifdef TEST
gets(a);
#endif
int i;
for(i=0;a[i]!='\0';i++){
if(charset.test(a[i]-'a')) {
repeat.set(a[i]-'a');
}
charset.set(a[i]-'a');
}
for(int j=0;j<i;j++)
{
if(!repeat.test(a[j]-'a')){
cout<<a[j]<<endl;
return 0;
}
}
cerr<<"No non repeating Character"<<endl;
return 0;
On Sun, Sep 11, 2011 at 9:16 PM, Kamakshii Aggarwal
<kamakshi...@gmail.com>wrote:
> @neha:can u pls explain ur method?
>
>
> On Sun, Sep 11, 2011 at 9:09 PM, sukran dhawan <sukrandha...@gmail.com>wrote:
>
>> ya +1 to neha use bitset concept in c++
>>
>>
>> On Sun, Sep 11, 2011 at 8:24 PM, Neha Singh
>> <neha.ndelhi.1...@gmail.com>wrote:
>>
>>> for ques 1 use bit manipulation
>>> its more efficient
>>>
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>
>
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> Kamakshi
> kamakshi...@gmail.com
>
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