For the mentioned scenario, it seems to be the only feasible solution.

On Sun, Sep 18, 2011 at 3:57 AM, bharatkumar bagana <
bagana.bharatku...@gmail.com> wrote:

> @anup : the time complexity will be very high ... O(n*M*M)...n=#characters
> to be checked...M=size of the matrix ...
>
>
> On Sat, Sep 17, 2011 at 8:30 AM, Anup Ghatage <ghat...@gmail.com> wrote:
>
>> As WgpShashank once pointed out.
>>
>> Search the whole matrix for the first character instances, for each
>> instance, send the array, string and that char's position to a function that
>> will recursively check its direct neighbors for the next character.
>> Exhaustively check like that for each starting characters appearance till
>> you find the string, if any.
>>
>> On Fri, Sep 16, 2011 at 11:55 PM, Ankur Garg <ankurga...@gmail.com>wrote:
>>
>>> In a matrix of. characters, find an string. String can be in any way (all
>>> 8 neighbours to be considered)
>>> like find Microsoft in below matrix.
>>>
>>>  A
>>> C
>>> P
>>> *R
>>> *C*
>>> *X
>>> *S
>>> **O
>>> *P
>>> *C*
>>> V
>>> *O*
>>> V
>>> N
>>> *I*
>>> W
>>>  G
>>> *F
>>> **M
>>> *N
>>> Q
>>>  A
>>> *T*
>>> I
>>> T
>>>
>>>  *Any Ideas How to Solve/Approach this problem ?*
>>>
>>>
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>>
>>
>>
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>> Anup Ghatage
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>
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-- 
Anup Ghatage

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