hmm, nice questions, can we create an  efficient DS to query the
strings ??


tried using trie but memory prints are very large ( O(n^2) )? :-((



On Sep 18, 12:59 pm, Anup Ghatage <ghat...@gmail.com> wrote:
> For the mentioned scenario, it seems to be the only feasible solution.
>
> On Sun, Sep 18, 2011 at 3:57 AM, bharatkumar bagana <
>
>
>
>
>
>
>
>
>
> bagana.bharatku...@gmail.com> wrote:
> > @anup : the time complexity will be very high ... O(n*M*M)...n=#characters
> > to be checked...M=size of the matrix ...
>
> > On Sat, Sep 17, 2011 at 8:30 AM, Anup Ghatage <ghat...@gmail.com> wrote:
>
> >> As WgpShashank once pointed out.
>
> >> Search the whole matrix for the first character instances, for each
> >> instance, send the array, string and that char's position to a function 
> >> that
> >> will recursively check its direct neighbors for the next character.
> >> Exhaustively check like that for each starting characters appearance till
> >> you find the string, if any.
>
> >> On Fri, Sep 16, 2011 at 11:55 PM, Ankur Garg <ankurga...@gmail.com>wrote:
>
> >>> In a matrix of. characters, find an string. String can be in any way (all
> >>> 8 neighbours to be considered)
> >>> like find Microsoft in below matrix.
>
> >>>  A
> >>> C
> >>> P
> >>> *R
> >>> *C*
> >>> *X
> >>> *S
> >>> **O
> >>> *P
> >>> *C*
> >>> V
> >>> *O*
> >>> V
> >>> N
> >>> *I*
> >>> W
> >>>  G
> >>> *F
> >>> **M
> >>> *N
> >>> Q
> >>>  A
> >>> *T*
> >>> I
> >>> T
>
> >>>  *Any Ideas How to Solve/Approach this problem ?*
>
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> >> --
> >> Anup Ghatage
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> > *BharatKumar Bagana*
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> Anup Ghatage

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