@nitin Plz explain how u have reached answer of question no. 4 and 6
On 19-Sep-2011 12:26 AM, "Nitin Garg" <nitin.garg.i...@gmail.com> wrote:
>
> Answer  3 - 100
> Answer 6 - 103
> Answer 4 - 194 total processes including the parent
> Answer 7 - 12 km south, 12 km east
>
>
> On Sun, Sep 18, 2011 at 11:53 PM, Ashima . <ashima.b...@gmail.com> wrote:
>>
>> @malay: how cm n+logn-2?
>> cn u explain the logic ?
>>
>> Ashima
>> M.Sc.(Tech)Information Systems
>> 4th year
>> BITS Pilani
>> Rajasthan
>>
>>
>>
>>
>> On Sun, Sep 18, 2011 at 11:07 AM, Ashima . <ashima.b...@gmail.com> wrote:
>>>
>>> rite! 62.5%
>>>
>>> Ashima
>>> M.Sc.(Tech)Information Systems
>>> 4th year
>>> BITS Pilani
>>> Rajasthan
>>>
>>>
>>>
>>>
>>> On Sat, Sep 17, 2011 at 9:04 PM, malay chakrabarti <m1234...@gmail.com>
wrote:
>>>>
>>>> create a tournament tree.in each round one value is eliminated to
obtain in the process the winner or the highest value in n-1 comparisons.
Then check the queue of the winner which contains log(n) entries of the
values beaten by the winner which implicitly will contain the runners
up.Then log(n)-1 comparisons to find the highest among all the losers whom
the winner had beaten. So all over complexity will be n-1 +log(n) -1 =
n+log(n)-2. Hp that answers ur query. nice question btw :)
>>>>
>>>>
>>>> On Sun, Sep 18, 2011 at 8:02 AM, VIHARRI <viharri....@gmail.com> wrote:
>>>>>
>>>>> hey i'm also thinking n + logn -2.. but couldnt able to figure out
>>>>> how??? can you please explain the logic
>>>>>
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>
>
>
> --
> Nitin Garg
>
> "Personality can open doors... but only Character can keep them open"
>
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