For question 2 see ashima link.
On 19-Sep-2011 1:43 PM, "Nitin Garg" <nitin.garg.i...@gmail.com> wrote:
>
> Can someone tell answers to question 2 and 5 with explanation??
>
>
>
>
> On Mon, Sep 19, 2011 at 1:40 PM, Nitin Garg <nitin.garg.i...@gmail.com>
wrote:
>>
>> In Question 4 i just kept counting new processes that are being added in
every iteration.
>> No. of new processes being created is equal to the already running no. of
even pid processes.
>>
>> Time - PId
>> 0  - 0                          1
>> 1 - 0,1                        2
>> 2, - 0,1,2                    3
>> 3, - 0,1,2,3,4              5
>> 4 - 0,1,2,3,4,5,6,7       8
>> .
>> .
>> .
>>
>>
>>
>> 1,2,3,5,8,11,17,25,38,57,86,129,194
>>
>> I kept counting, got 194.
>> Don't know of any shortcut.
>>
>>
>>
>>
>>
>> On Mon, Sep 19, 2011 at 1:35 PM, Nitin Garg <nitin.garg.i...@gmail.com>
wrote:
>>>
>>> Question 6 -
>>> Intuitively you can see that the greater the sum is, the greater the
favorable events in sample space.
>>>
>>> e.g. - sum = 1 .. cases {(1)}   Pr = 1/6
>>> sum = 2             cases {(2),(1,1)}   Pr = 1/6 + 1/36
>>> sum = 3            cases {(3),(2,1)(1,2)(1,1,1)}  Pr = 1/6 + 1/36 +1/36
+ 1/216
>>>
>>>
>>> for a more formal proof, look at the recursion -
>>>
>>>
>>> P(k) = (P(k-6) + P(k-5) + P(k-4)... P(k-1)))/6
>>>
>>> where P(0) = 1, P(i) = 0  for i<0
>>>
>>> Base case -
>>> P(2) > P(1)
>>>
>>> Hypothesis -
>>>
>>> P(i) > P(i-1) for  all i <= k
>>>
>>> To prove
>>> P(k+1)  > P(k)
>>>
>>> Proof
>>> P(k+1) - P(k) = (P(k) - P(k-6))/6 > 0
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>> On Mon, Sep 19, 2011 at 1:04 PM, Nitin Garg <nitin.garg.i...@gmail.com>
wrote:
>>>>
>>>> Question 3 -
>>>> To eliminate one player, you need to host atleast 2 matches and make
him loose in both 2. These 2 matches can not contribute to elimination of
any other player.
>>>> So, min 2 matches for every player who is to be eliminated, hence 100.
>>>>
>>>>
>>>> On Mon, Sep 19, 2011 at 11:54 AM, Bhanu Chowdary <
bhanuchowd...@gmail.com> wrote:
>>>>>
>>>>> @Nitin: Answer to question 3 is 50.
>>>>>
>>>>>
>>>>> On Mon, Sep 19, 2011 at 11:44 AM, praveen raj <praveen0...@gmail.com>
wrote:
>>>>>>
>>>>>> @nitin Plz explain how u have reached answer of question no. 4 and 6
>>>>>>
>>>>>>
>>>>>> On 19-Sep-2011 12:26 AM, "Nitin Garg" <nitin.garg.i...@gmail.com>
wrote:
>>>>>> >
>>>>>> > Answer  3 - 100
>>>>>> > Answer 6 - 103
>>>>>> > Answer 4 - 194 total processes including the parent
>>>>>> > Answer 7 - 12 km south, 12 km east
>>>>>> >
>>>>>> >
>>>>>> > On Sun, Sep 18, 2011 at 11:53 PM, Ashima . <ashima.b...@gmail.com>
wrote:
>>>>>> >>
>>>>>> >> @malay: how cm n+logn-2?
>>>>>> >> cn u explain the logic ?
>>>>>> >>
>>>>>> >> Ashima
>>>>>> >> M.Sc.(Tech)Information Systems
>>>>>> >> 4th year
>>>>>> >> BITS Pilani
>>>>>> >> Rajasthan
>>>>>> >>
>>>>>> >>
>>>>>> >>
>>>>>> >>
>>>>>> >> On Sun, Sep 18, 2011 at 11:07 AM, Ashima . <ashima.b...@gmail.com>
wrote:
>>>>>> >>>
>>>>>> >>> rite! 62.5%
>>>>>> >>>
>>>>>> >>> Ashima
>>>>>> >>> M.Sc.(Tech)Information Systems
>>>>>> >>> 4th year
>>>>>> >>> BITS Pilani
>>>>>> >>> Rajasthan
>>>>>> >>>
>>>>>> >>>
>>>>>> >>>
>>>>>> >>>
>>>>>> >>> On Sat, Sep 17, 2011 at 9:04 PM, malay chakrabarti <
m1234...@gmail.com> wrote:
>>>>>> >>>>
>>>>>> >>>> create a tournament tree.in each round one value is eliminated
to obtain in the process the winner or the highest value in n-1 comparisons.
Then check the queue of the winner which contains log(n) entries of the
values beaten by the winner which implicitly will contain the runners
up.Then log(n)-1 comparisons to find the highest among all the losers whom
the winner had beaten. So all over complexity will be n-1 +log(n) -1 =
n+log(n)-2. Hp that answers ur query. nice question btw :)
>>>>>> >>>>
>>>>>> >>>>
>>>>>> >>>> On Sun, Sep 18, 2011 at 8:02 AM, VIHARRI <viharri....@gmail.com>
wrote:
>>>>>> >>>>>
>>>>>> >>>>> hey i'm also thinking n + logn -2.. but couldnt able to figure
out
>>>>>> >>>>> how??? can you please explain the logic
>>>>>> >>>>>
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>>>>>> >>>
>>>>>> >>>
>>>>>> >>
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>>>>>> >
>>>>>> >
>>>>>> >
>>>>>> >
>>>>>> > --
>>>>>> > Nitin Garg
>>>>>> >
>>>>>> > "Personality can open doors... but only Character can keep them
open"
>>>>>> >
>>>>>> > --
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>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Bhanu Chowdary
>>>>>
>>>>> --
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>>>>
>>>>
>>>>
>>>>
>>>> --
>>>> Nitin Garg
>>>>
>>>> "Personality can open doors... but only Character can keep them open"
>>>
>>>
>>>
>>>
>>> --
>>> Nitin Garg
>>>
>>> "Personality can open doors... but only Character can keep them open"
>>
>>
>>
>>
>> --
>> Nitin Garg
>>
>> "Personality can open doors... but only Character can keep them open"
>
>
>
>
> --
> Nitin Garg
>
> "Personality can open doors... but only Character can keep them open"
>
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