int a=256;
imagine integer is 4 bytes.
so in memory it will look like this
00000000--last byte..
00000000
00000001------- p
00000000---starting byte of a
but the char pointer is pointing to 1 byte of integer,
u incremented it point to 2nd byte
and assigned the new value 2(it was 1 before)
so it became 512..
00000000
00000000
00000010----p
00000000 ---- a
On Thu, Sep 22, 2011 at 6:21 PM, rohit jangid <rohit.nsi...@gmail.com>wrote:
> isn't that simply because if little indian endian way of storing bytes in
> memory
>
> initial -- 00000000 00000001 0......
> finally-- 00000000 00000010 0......
>
> On Sep 22, 2011 5:38 PM, "Rohit Upadhyaya" <mailtoroh...@gmail.com> wrote:
> >
> > int main()
> > {
> > int a=256;
> > char *p=&a;
> > *++p=2;
> > printf("%d",a);
> > return(0);
> > }
> >
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