1. don't use dev c
2. search archives
3. after doing 2 you will say it is not there,
therefore solution by sunny -
char five[7] -> string of length 7
charlie -> 7 length string
declare it as char[8] u will get expected output
On Sat, Oct 8, 2011 at 4:14 PM, SHIVAM AGRAWAL <shivi...@gmail.com> wrote:
> when i am running this on dev c it is printing times but on running in
> linux it is not printing times plz any1 xplain me y is it so????
>
>
> #include<stdio.h>
> main()
> {
> char outline[50];
> char one[7],two[7],four[7],five[7];
> int three;
> sprintf(outline,"this is %d tim %s \n",10,"charlie");
> printf("%s",outline);
> sscanf(outline,"%s %s %d %s %s",&one,&two,&three,&four,&five);
> printf("%s\n",one);
> printf("%s\n",two);
> printf("%d\n",three);
> printf("%s\n",four);
> printf("%s\n",five);
> }
>
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