@Ashima: It is a hypothetical question assuming an infinite array,
which of course requires infinite memory. So don't worry about the
compiler and other practical considerations. In real life the mass of
the memory would cause it to collapse into a singularity long before
the compiler would become an issue. Because we know that the array is
sorted, we'll need a binary search at some point. But at first we
don't know the bounds of the search. We must first find an index in
the array which contains a value greater than or equal to the value
we're searching for. Then we can do a binary search. To find that
index, you could start at i=1 and double i until A[i] >= the value you
are searching for. My method uses something like Newton's Method which
will converge more quickly in some cases. It assumes that the slope is
fairly consistent, which may or may not be a good assumption.

Don

On Sep 30, 10:00 am, "Ashima ." <ashima.b...@gmail.com> wrote:
> isnt this quest a lil wrong. coz suppose if i dnt know the length of an
> array,then how will i  access the last element of the array.in such  a
> case,i will almost traverse the whole memory and still not stop. coz
> compiler does not give array out of bound exception.
> Ashima
> M.Sc.(Tech)Information Systems
> 4th year
> BITS Pilani
> Rajasthan
>
> On Fri, Sep 30, 2011 at 6:06 PM, pssaravanan
> <saravananselvam...@gmail.com>wrote:
>
> > If the length of the array s not known,v could not apply the binary
> > search to search for an element. i think following code will produce
> > better solution.
>
> > i = 0;
> > for(i = 0;A[i] < p&& A[i] !=NULL;i = (i+1)^2);
> > j = i;
> > i = sqrt(i)-1;
> > applybinarysearch(i,j);
>
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