but it is ++(*ptr)
i mean valure at ptr is incremented......n hw AN when we have written
%c,,,,i cant get dat
On Sat, Oct 1, 2011 at 6:47 PM, SAMM <somnath.nit...@gmail.com> wrote:
> Think pointer as an array , then u can understand the problm.
> Here *ptr=TAN ; so ptr points to the First adress of the string . when
> u do increment it just point to the next address and Thus is gives
> "AN" .
>
> On 10/1/11, rahul sharma <rahul23111...@gmail.com> wrote:
> > void main()
> >
> > {
> > void *ptr;
> > char *a='A';
> > char *b="TAN";
> > int i=50;
> > ptr=a;
> > ptr=(*char)malloc(sizeof(a));
> > printf("%c",*ptr);
> > ptr=i;
> > ptr=(*int)malloc(sizeof(i));
> > printf("%d",++(*ptr));
> > ptr=b;
> > ptr=(*char)malloc(sizeof(b));
> > printf("%c",++(*ptr));
> >
> > }
> > Ans: A51AN
> >
> >
> > int his o/p int last printf it is %c but hw it is printing a two
> character
> > string????AN????isn't it a51 n then ++(*ptr) ++(T) so it become *U*
> > *
> > *
> > *isnt it a51U*
> > *
> > *
> > *
> > *
> > *but above ans is correct...*
> > *
> > *
> > *explain plz*
> >
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> Somnath Singh
>
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