yeah...i have got it from somewhr i thought that in hurry someone had posted
it in wrong syntax......like changing (*char) to (*char)
On Sat, Oct 1, 2011 at 9:43 PM, Akash Mukherjee <akash...@gmail.com> wrote:
> hey...d code doesn't compile on gcc though
>
>
> On Sat, Oct 1, 2011 at 7:32 PM, rahul sharma <rahul23111...@gmail.com>wrote:
>
>> but it is ++(*ptr)
>>
>> i mean valure at ptr is incremented......n hw AN when we have written
>> %c,,,,i cant get dat
>>
>>
>> On Sat, Oct 1, 2011 at 6:47 PM, SAMM <somnath.nit...@gmail.com> wrote:
>>
>>> Think pointer as an array , then u can understand the problm.
>>> Here *ptr=TAN ; so ptr points to the First adress of the string . when
>>> u do increment it just point to the next address and Thus is gives
>>> "AN" .
>>>
>>> On 10/1/11, rahul sharma <rahul23111...@gmail.com> wrote:
>>> > void main()
>>> >
>>> > {
>>> > void *ptr;
>>> > char *a='A';
>>> > char *b="TAN";
>>> > int i=50;
>>> > ptr=a;
>>> > ptr=(*char)malloc(sizeof(a));
>>> > printf("%c",*ptr);
>>> > ptr=i;
>>> > ptr=(*int)malloc(sizeof(i));
>>> > printf("%d",++(*ptr));
>>> > ptr=b;
>>> > ptr=(*char)malloc(sizeof(b));
>>> > printf("%c",++(*ptr));
>>> >
>>> > }
>>> > Ans: A51AN
>>> >
>>> >
>>> > int his o/p int last printf it is %c but hw it is printing a two
>>> character
>>> > string????AN????isn't it a51 n then ++(*ptr) ++(T) so it become *U*
>>> > *
>>> > *
>>> > *isnt it a51U*
>>> > *
>>> > *
>>> > *
>>> > *
>>> > *but above ans is correct...*
>>> > *
>>> > *
>>> > *explain plz*
>>> >
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>>>
>>>
>>> --
>>> Somnath Singh
>>>
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