use DFS. at any poit of time if u find a node such that it has no left
and right child, then you are at leaf. find sum of all values in the
stack. for that u can use another stack.

On Oct 7, 4:15 pm, Deepak arora <deepakarora...@gmail.com> wrote:
> Please tell the algo of this problem....
>
> hasPathSum()
> We'll define a "root-to-leaf path" to be a sequence of nodes in a tree
> starting with the root node and proceeding
> downward to a leaf (a node with no children). We'll say that an empty
> tree contains no root-to-leaf paths. So for
> example, the following tree has exactly four root-to-leaf paths:
>     5
>   /     \
> 4       8
> /        / \
> 11    13 4
> /   \         \
> 7   2         1
> Root-to-leaf paths:
> path 1: 5 4 11 7
> path 2: 5 4 11 2
> path 3: 5 8 13
> path 4: 5 8 4 1
> For this problem, we will be concerned with the sum of the values of
> such a path -- for example, the sum of the
> values on the 5-4-11-7 path is 5 + 4 + 11 + 7 = 27.
>
> thanks..

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