@Shiva, not necessarily in upper half
take the transpose of example put by Dave and see by yourself
There are few observations for this question:
1. kth smallest will always lie in first k*k matrix
2. it wont be part of sqrt(k)*sqrt(k) matrix
Thus rest all need to be searched recursively to find the element
Any suggestions ?
On Oct 10, 10:55 am, "shiva@Algo" <shiv.jays...@gmail.com> wrote:
> id we see the pattern then we can easily find that the kth smallest element
> lie on the upper half of the k*k submatrix(on the upperleft corner )
> we can do search on (k*k)/2 elements to find that
>
> On Mon, Oct 10, 2011 at 10:36 AM, Dave <dave_and_da...@juno.com> wrote:
> > @Shubham: So if the matrix is
> > 1 2
> > 3 4
> > and you want the 2nd smallest, are you saying that it is 4?
>
> > Dave
>
> > On Oct 9, 7:40 pm, shubham goyal <shubhamgoyal.n...@gmail.com> wrote:
> > > im assuming it be a square matrix
> > > then kth smallest element will be in a first k*k sub matrix.
> > > jst look for smallest element in the diagonal of this matrix.
> > > it will give the kth smallest element .
>
> > > On Mon, Oct 10, 2011 at 4:45 AM, Ankur Garg <ankurga...@gmail.com>
> > wrote:
> > > > Given a 2D matrix which is both row wise and column wise sorted.
> > Propose an
> > > > algorithm for finding the kth smallest element in it in least time
> > > > complexity
>
> > > > A General Max Heap can be used with k space and n+klogk complexity
>
> > > > Any other solution or even a way by which we dont scan the whole
> > matrix to
> > > > find the solution ?
>
> > > > I
>
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