@ Karthikeyan :
sum of cubes fails:-
arr1={2,3,0,-3} = 4
arr2={1,1,1,1} = 4
On Wed, Jan 4, 2012 at 6:53 PM, Karthikeyan V.B <kartmu...@gmail.com> wrote:
> Hi,
>
> Consider, arr1={1,2,3} and arr2={-1,-2,-3}
>
> using sum of squares method sum(arr1) = 14 ans sum(arr2) = 14 (since
> square of 1 and -1 is 1)
>
> so it won work with this case
>
> 1.better take the square and negate it before adding
> or
> 2.take sum of cubes
>
> pls correct me if i'm wrong
>
> Regards,
> Karthikeyan
> PSG TECH
>
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