@Shashank: can you look at the first post from you? you are calculating 3^a[i] & adding it to the sum,
can you write a pseudocode so that none of gets confused. (also, if you are saying this. for each element, raise element to the power of 2 (2^a[i]), (like you said in above post), or 3, like in original post, and add all these.. if this is your logic, there should be a mathematical proof that proves the one-one property) yours may work, I don't deny but there should be some proof if it isn't very obvious to know. again, let me know If I went wrong anywhere.. also, post pseudo code, to avoid confusion.. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/osYFu3m7QwoJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
