output depends on sizeof(int)....so it may be different if you run on
different compilers.
considering *sizeof(int) = 2;*
argv[] is array of pointers.
(p+=sizeof(int))[-1];
p=p+2 // 2=sizeof(int);
now p will be pointing at index *argv[2];
then you are doing....
p=p-1;
i.e p will point to *argv[1]
hence output will be
o/p = cd
On Thu, Jan 26, 2012 at 10:53 PM, rahul sharma <rahul23111...@gmail.com>wrote:
> #include<stdio.h>
> #include<conio.h>
> void fun(char **);
>
> int main()
> {
> char *argv[]={"ab","cd","de","fg"};
> fun(argv);
> getch();
> return 0;
> }
>
> void fun(char **p)
> {
> char *t;
> t=(p+=sizeof(int))[-1];
> printf("%s\n",t);
> }
>
> o/p: fg
>
> can nyone xplain
>
> the 2nd statement in fun?????
>
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