[-1] in end is same as -1 ??????
On Thu, Jan 26, 2012 at 11:11 PM, atul anand <atul.87fri...@gmail.com>wrote:
> btw your compiler has sizeof(int)=4;
> thats why o/p = fg
>
> On Thu, Jan 26, 2012 at 11:09 PM, atul anand <atul.87fri...@gmail.com>wrote:
>
>> output depends on sizeof(int)....so it may be different if you run on
>> different compilers.
>>
>> considering *sizeof(int) = 2;*
>>
>> argv[] is array of pointers.
>> (p+=sizeof(int))[-1];
>> p=p+2 // 2=sizeof(int);
>>
>> now p will be pointing at index *argv[2];
>> then you are doing....
>>
>> p=p-1;
>>
>> i.e p will point to *argv[1]
>>
>> hence output will be
>> o/p = cd
>>
>> On Thu, Jan 26, 2012 at 10:53 PM, rahul sharma
>> <rahul23111...@gmail.com>wrote:
>>
>>> #include<stdio.h>
>>> #include<conio.h>
>>> void fun(char **);
>>>
>>> int main()
>>> {
>>> char *argv[]={"ab","cd","de","fg"};
>>> fun(argv);
>>> getch();
>>> return 0;
>>> }
>>>
>>> void fun(char **p)
>>> {
>>> char *t;
>>> t=(p+=sizeof(int))[-1];
>>> printf("%s\n",t);
>>> }
>>>
>>> o/p: fg
>>>
>>> can nyone xplain
>>>
>>> the 2nd statement in fun?????
>>>
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>>
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