Actually i had evaluated x=(++i + ++i); separately with i=2;
but i was amazed to get answer as 8... can u elaborate it

On Mon, Feb 13, 2012 at 4:09 PM, Rahul <raikra...@gmail.com> wrote:
> Here you go then :
> ++ i becomes 3
> second bracket becomes 5 ( 3+2)
>
>
> first bracket is 4
>
> 4 * 5 = 20
> But you are adding ONE to i FOUR times
> hence the answer you get is 4 plus the computation of previous line
>
> Hope I AM correct :
>
>
>
>
> On Mon, Feb 13, 2012 at 3:56 PM, Ratan <success.rata...@gmail.com> wrote:
>>
>> can any1 explain the working of the above expression in any of the
>> compiler..... I jzz want to knw how the computation takes place in gcc
>> compiler..
>>
>> On Sun, Feb 12, 2012 at 11:03 PM, Kartik Sachan <kartik.sac...@gmail.com>
>> wrote:
>> > its a compiler depentent...
>> >
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Ratan | 3rd Year | Information Technology | NIT ALLAHABAD

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