Azhar,

Thanks for the answer. Its a great explanation.

Cheers,
Mani

On Mon, Feb 13, 2012 at 7:50 PM, Azhar Hussain <azhar...@gmail.com> wrote:

> C, standard says which operand belongs to which operator. It does not says
> which one gets evaluated first.
> Why it is returning 8 is because of sequence point. It tells that, all the
> side effects of a value are resolved before an operation is performed.
> In your case ++i + ++i evaluates like this on gcc 4.2
>           ++2 which is 3
>           ++3 which is 4
> now sequence point is resolved both i + i is added to yield 8.
> You should not use such expression
>
> More information can be found at
> http://c-faq.com/expr/seqpoints.html
> http://en.wikipedia.org/wiki/Sequence_point
>
> -
> Azhar.
>
>
> On Mon, Feb 13, 2012 at 7:38 PM, Ratan <success.rata...@gmail.com> wrote:
>
>> Actually i had evaluated x=(++i + ++i); separately with i=2;
>> but i was amazed to get answer as 8... can u elaborate it
>>
>> On Mon, Feb 13, 2012 at 4:09 PM, Rahul <raikra...@gmail.com> wrote:
>> > Here you go then :
>> > ++ i becomes 3
>> > second bracket becomes 5 ( 3+2)
>> >
>> >
>> > first bracket is 4
>> >
>> > 4 * 5 = 20
>> > But you are adding ONE to i FOUR times
>> > hence the answer you get is 4 plus the computation of previous line
>> >
>> > Hope I AM correct :
>> >
>> >
>> >
>> >
>> > On Mon, Feb 13, 2012 at 3:56 PM, Ratan <success.rata...@gmail.com>
>> wrote:
>> >>
>> >> can any1 explain the working of the above expression in any of the
>> >> compiler..... I jzz want to knw how the computation takes place in gcc
>> >> compiler..
>> >>
>> >> On Sun, Feb 12, 2012 at 11:03 PM, Kartik Sachan <
>> kartik.sac...@gmail.com>
>> >> wrote:
>> >> > its a compiler depentent...
>> >> >
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Thanks & Regards,
Mani
http://www.sanidapa.com - The music Search engine

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