Navin , your reply is correct.

On Sat, May 19, 2012 at 10:36 PM, Gene <gene.ress...@gmail.com> wrote:

> The problem is not so clear, so you must make some assumptions to gat
> an answer. Since we have water, we have to envision the histogram in
> 3d. Then assume that the distance between histogram bars is 1 and bar
> i has height H[i], 0<=i<N, zero width and unit depth, and the base
> plane is at zero. Water is held in the "pockets" between bars.  Then
> the "pocket" between H[i] and H[i+1] holds min(H[i],H[i+1]).  To get
> the total, just sum these for 0 <= i < N-1 .
>
> On May 17, 1:57 am, Nikhil Agarwal <nikhil.bhoja...@gmail.com> wrote:
> > Imagine that you have an histogram stored in an array. Now imagine that
> you
> > can pour water on top of your histogram. Describe an algorithm that
> > computes the amount of water that remains trapped among the columns of
> the
> > graph. Clearly on the edges the water would fall off. Use the language or
> > the pseudocode you prefer.
> >
> > --
> > Thanks & Regards
> > Nikhil Agarwal
> > B.Tech. in Computer Science & Engineering
> > National Institute Of Technology,
> Durgapur,Indiahttp://tech-nikk.blogspot.comhttp://
> beta.freshersworld.com/communities/nitd
>
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>


-- 
Thanks & Regards
Nikhil Agarwal
B.Tech. in Computer Science & Engineering
National Institute Of Technology, Durgapur,India
http://tech-nikk.blogspot.com
http://beta.freshersworld.com/communities/nitd

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