lets say we have an array COUNT[256] which is initialized to zero. 1) traverse the string S from 0 to length-1 2) if COUNT[S[i] - '0'] == 0 , increment COUNT[S[i] - '0'] = 1; 3) else print the first repeating character.
-Mahesh On Fri, Jun 8, 2012 at 2:26 PM, Anika Jain <anika.jai...@gmail.com> wrote: > you will have to note time for of occurence of a character for all chars > > > On Fri, Jun 8, 2012 at 2:15 PM, himanshu kansal < > himanshukansal...@gmail.com> wrote: > >> how can we find 1st repeating character in string??? >> e.g. if the string is "abba" it should return 'b' and not 'a'..... >> >> note: hashing will give the answer as 'a'.... >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > > -- > Regards > Anika Jain > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.