Here, we can use hashmap and use an extra variable max_till_now that will keep track of maximum element occured to us till now while updating.
Time complexity of solution will be O(n) max_till_now = 0; for ( int i = 0; i < arr.size(); i++ ) { hashmap[arr[i]] += 1; if ( hashmap[arr[i]] > max_till_now ) max_till_now = hashmap[arr[i]]; } print(max_till_now); -- Akshat Sapra Under Graduation(B.Tech) IIIT-Allahabad(Amethi Campus) *--------------------------------------* sapraaks...@gmail.com akshatsapr...@gmail.com rit20009008@ <rit20009...@gmail.com>iiita.ac.in -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.