Why will my proposed solution not work for you ???

On Wed, Jun 20, 2012 at 8:19 PM, Navin Kumar <algorithm.i...@gmail.com>wrote:

> @Kirubakaran : still space complexity is O(n) due to stack.Can it be
> solved in space complexity O(1).
>
>
> On Wed, Jun 20, 2012 at 8:00 PM, Kirubakaran D <kirubakara...@gmail.com>wrote:
>
>> You could use recursion.
>>
>> def reverse_Q q
>> if !q.isEmpty?
>>   el = q.dequeue
>>   nQ = reverse_Q(q)
>>   nQ.enqueue el
>>   return nQ
>> end
>> return q
>> end
>>
>>
>>
>> On Wednesday, June 20, 2012 6:57:23 PM UTC+5:30, Navin Kumar wrote:
>>>
>>> Use only standard operation of Queue like: EnQueue, DeQueue,
>>> IsEmptyQueue etc
>>>
>>> On Wed, Jun 20, 2012 at 6:50 PM, amrit harry <dabbcomput...@gmail.com>wrote:
>>>
>>>> can we create other methods or we have to use only enqueue and
>>>> dequeue...? if yes then simply
>>>> for(i=0;i<=n/2;i++)
>>>> swap(i,n-i);
>>>>
>>>>
>>>>
>>>> On Wed, Jun 20, 2012 at 6:46 PM, Navin Kumar 
>>>> <algorithm.i...@gmail.com>wrote:
>>>>
>>>>> @Saurabh: queue will be remain unchanged according to your algorithm.
>>>>> Because if you will delete an element from front and add at rear no change
>>>>> will be there. After n iteration front will be pointing to same element 
>>>>> and
>>>>> rear will also point to same element.
>>>>>
>>>>> Correct me if i am wrong. :)
>>>>>
>>>>>
>>>>> On Wed, Jun 20, 2012 at 6:39 PM, saurabh singh <saurabh.n...@gmail.com
>>>>> > wrote:
>>>>>
>>>>>> count the size of queue : O(n)
>>>>>> loop for n and do remove and add in queue : O(n)
>>>>>>
>>>>>> Total : O(n)
>>>>>>
>>>>>>
>>>>>> On Wed, Jun 20, 2012 at 6:34 PM, Navin Kumar <
>>>>>> algorithm.i...@gmail.com> wrote:
>>>>>>
>>>>>>> How to reverse a Queue .
>>>>>>>
>>>>>>> Constraints: Time complexity O(n). space complexity: O(1)
>>>>>>>
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>>>>>>
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>>>>>> --
>>>>>> Thanks & Regards,
>>>>>> Saurabh
>>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> Thanks & Regards
>>>> Amritpal singh
>>>>
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-- 
Thanks & Regards,
Saurabh

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