@Saurabh:i was wrong in deciding space complexity. Yes, your algo will take
O(1) time but you have to enqueue elements in reverse order.Not in the
order you fetched. Think about it :). Then you have to take stack or some
other data structure.

On Wed, Jun 20, 2012 at 8:40 PM, saurabh singh <saurabh.n...@gmail.com>wrote:

> How ??
> I am asking to manipulate the same queue.
> Dequeue n-1 elements and enqueue them in order to you take out to the same
> queue..Where is extra space involved ?
>
>
> On Wed, Jun 20, 2012 at 8:36 PM, Navin Kumar <algorithm.i...@gmail.com>wrote:
>
>> @saurabh : i want solution with space complexity of O(1) . your solution
>> is right but it takes O(n) space.
>>
>>
>> On Wed, Jun 20, 2012 at 8:28 PM, saurabh singh <saurabh.n...@gmail.com>wrote:
>>
>>> Why will my proposed solution not work for you ???
>>>
>>>
>>> On Wed, Jun 20, 2012 at 8:19 PM, Navin Kumar 
>>> <algorithm.i...@gmail.com>wrote:
>>>
>>>> @Kirubakaran : still space complexity is O(n) due to stack.Can it be
>>>> solved in space complexity O(1).
>>>>
>>>>
>>>> On Wed, Jun 20, 2012 at 8:00 PM, Kirubakaran D <kirubakara...@gmail.com
>>>> > wrote:
>>>>
>>>>> You could use recursion.
>>>>>
>>>>> def reverse_Q q
>>>>> if !q.isEmpty?
>>>>>   el = q.dequeue
>>>>>   nQ = reverse_Q(q)
>>>>>   nQ.enqueue el
>>>>>   return nQ
>>>>> end
>>>>> return q
>>>>> end
>>>>>
>>>>>
>>>>>
>>>>> On Wednesday, June 20, 2012 6:57:23 PM UTC+5:30, Navin Kumar wrote:
>>>>>>
>>>>>> Use only standard operation of Queue like: EnQueue, DeQueue,
>>>>>> IsEmptyQueue etc
>>>>>>
>>>>>> On Wed, Jun 20, 2012 at 6:50 PM, amrit harry <dabbcomput...@gmail.com
>>>>>> > wrote:
>>>>>>
>>>>>>> can we create other methods or we have to use only enqueue and
>>>>>>> dequeue...? if yes then simply
>>>>>>> for(i=0;i<=n/2;i++)
>>>>>>> swap(i,n-i);
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> On Wed, Jun 20, 2012 at 6:46 PM, Navin Kumar <
>>>>>>> algorithm.i...@gmail.com> wrote:
>>>>>>>
>>>>>>>> @Saurabh: queue will be remain unchanged according to your
>>>>>>>> algorithm. Because if you will delete an element from front and add at 
>>>>>>>> rear
>>>>>>>> no change will be there. After n iteration front will be pointing to 
>>>>>>>> same
>>>>>>>> element and rear will also point to same element.
>>>>>>>>
>>>>>>>> Correct me if i am wrong. :)
>>>>>>>>
>>>>>>>>
>>>>>>>> On Wed, Jun 20, 2012 at 6:39 PM, saurabh singh <
>>>>>>>> saurabh.n...@gmail.com> wrote:
>>>>>>>>
>>>>>>>>> count the size of queue : O(n)
>>>>>>>>> loop for n and do remove and add in queue : O(n)
>>>>>>>>>
>>>>>>>>> Total : O(n)
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On Wed, Jun 20, 2012 at 6:34 PM, Navin Kumar <
>>>>>>>>> algorithm.i...@gmail.com> wrote:
>>>>>>>>>
>>>>>>>>>> How to reverse a Queue .
>>>>>>>>>>
>>>>>>>>>> Constraints: Time complexity O(n). space complexity: O(1)
>>>>>>>>>>
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>>>>>>>>>
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> --
>>>>>>>>> Thanks & Regards,
>>>>>>>>> Saurabh
>>>>>>>>>
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>>>>>>>
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>>>>>>> Amritpal singh
>>>>>>>
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>>>
>>>
>>>
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>>> Saurabh
>>>
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>
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