@Vindhya
every time least is getting 101-'e' as the value. and not llo
as the statement
least = (*ptr<least ) ?(*ptr) :(least);
is equivalent to
if(*ptr<least)
least=*ptr;
so firstly it compares 127 with 'e' and least ='e'
in next iteration , it compares l and e, so agn least = 'e'
in next iteration , it compares l and e, so agn least = 'e'
in next iteration , it compares o and e, so agn least = 'e'
in next iteration , it compares null and e, so least = 0
i hope this will clarify your doubts
On Sun, Jul 15, 2012 at 11:57 PM, vindhya chhabra
<vindhyachha...@gmail.com>wrote:
> please someone explain
>
>
> On Sun, Jul 15, 2012 at 3:54 PM, vindhya chhabra <vindhyachha...@gmail.com
> > wrote:
>
>> #include <stdio.h>
>> main()
>> {
>> char * str = "hello";
>> char * ptr = str;
>> char least = 127;
>> while (*ptr++)
>> least = (*ptr<least ) ?(*ptr) :(least);
>> printf("%d",least);
>> getch();
>> }
>> in this ques i got o/p is 0(no doubt) but i have a doubt in why every
>> time least is getting 101-'e' as the value. why are ascii values of llo not
>> assigned in least. please someone explain.
>> --
>> Vindhya Chhabra
>>
>>
>>
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>
>
>
> --
> Vindhya Chhabra
>
>
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