thanks, i got it nw.
On Mon, Jul 16, 2012 at 12:45 AM, ashish jain <ashishjainco...@gmail.com>wrote:
> @Vindhya
>
> every time least is getting 101-'e' as the value. and not llo
> as the statement
> least = (*ptr<least ) ?(*ptr) :(least);
>
> is equivalent to
> if(*ptr<least)
> least=*ptr;
>
> so firstly it compares 127 with 'e' and least ='e'
> in next iteration , it compares l and e, so agn least = 'e'
> in next iteration , it compares l and e, so agn least = 'e'
> in next iteration , it compares o and e, so agn least = 'e'
> in next iteration , it compares null and e, so least = 0
>
> i hope this will clarify your doubts
>
>
> On Sun, Jul 15, 2012 at 11:57 PM, vindhya chhabra <
> vindhyachha...@gmail.com> wrote:
>
>> please someone explain
>>
>>
>> On Sun, Jul 15, 2012 at 3:54 PM, vindhya chhabra <
>> vindhyachha...@gmail.com> wrote:
>>
>>> #include <stdio.h>
>>> main()
>>> {
>>> char * str = "hello";
>>> char * ptr = str;
>>> char least = 127;
>>> while (*ptr++)
>>> least = (*ptr<least ) ?(*ptr) :(least);
>>> printf("%d",least);
>>> getch();
>>> }
>>> in this ques i got o/p is 0(no doubt) but i have a doubt in why every
>>> time least is getting 101-'e' as the value. why are ascii values of llo not
>>> assigned in least. please someone explain.
>>> --
>>> Vindhya Chhabra
>>>
>>>
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>>
>>
>>
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>> Vindhya Chhabra
>>
>>
>>
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