If we can retrieve ith prime efficiently, we can do the following...
1.maintain a prod=1, start from 1st element, say a[0]=n find n th prime
2.check if (prod% (ith_prime * ith_prime )==0) then return i;
           else prod=prod*ith_prime;
3.repeat it till end


On Thursday, 12 July 2012 10:55:02 UTC+5:30, algo bard wrote:
>
> Given an array of integers where some numbers repeat once, some numbers 
> repeat twice and only one number repeats thrice, how do you find the number 
> that gets repeated 3 times?
>
> Does this problem have an O(n) time and O(1) space solution?
> No hashmaps please!
>

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To view this discussion on the web visit 
https://groups.google.com/d/msg/algogeeks/-/TSPSKlD0FDsJ.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to