Sachin Chitale,
Dude the xoring operation will give us xor of numbers with freq 1 and 3 
respectively. How do you filter out the number with the frequency 3??

On Tuesday, February 12, 2013 11:44:08 PM UTC+5:30, Sachin Chitale wrote:
>
> use ex-or operation for all array elements..
> a^a=0
> a^a^a=a
>
>
> On Sun, Feb 10, 2013 at 8:22 AM, Mohanabalan D B 
> <mohana...@gmail.com<javascript:>
> > wrote:
>
>> can use counting sort
>>
>>
>> On Sun, Jul 15, 2012 at 6:37 PM, santosh thota 
>> <santosh...@gmail.com<javascript:>
>> > wrote:
>>
>>> If we can retrieve ith prime efficiently, we can do the following...
>>> 1.maintain a prod=1, start from 1st element, say a[0]=n find n th prime
>>> 2.check if (prod% (ith_prime * ith_prime )==0) then return i;
>>>            else prod=prod*ith_prime;
>>> 3.repeat it till end
>>>
>>>
>>>
>>> On Thursday, 12 July 2012 10:55:02 UTC+5:30, algo bard wrote:
>>>
>>>> Given an array of integers where some numbers repeat once, some numbers 
>>>> repeat twice and only one number repeats thrice, how do you find the 
>>>> number 
>>>> that gets repeated 3 times?
>>>>
>>>> Does this problem have an O(n) time and O(1) space solution?
>>>> No hashmaps please!
>>>>
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>
>
>
> -- 
> Regards,
> Sachin Chitale
> Application Engineer SCJP, SCWCD
> Contact# : +91 8086284349, 9892159511
> Oracle Corporation 
>

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